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/ \[ 2a + b = 6 \]
\[ 2a + b = 6 \]
February 22, 2026
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\( h(2) = 15 \) gives us \( a(2)^2 + b(2) + 3 = 15 \) which simplifies to \( 4a + 2b + 3 = 15 \). Thus, \( 4a + 2b = 12 \).
\( a + b = 5 \)
\( 4a + 2b = 12 \)
\[ (2a + b) - (a + b) = 6 - 5 \]
\[ 1 + b = 5 \]
\[ b = 4 \]
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