\frac{(4x+1) + (x+7) + (2x+4)}{3} = \frac{7x + 12}{3}.
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- a - 3 = 5 \implies a = 8 \quad \text{or} \quad a - 3 = -5 \implies a = -2.
- Sum: $ 8 + (-2) = 6 $. The answer is $ \boxed{6} $.
- Question: The average of $ 4x+1 $, $ x+7 $, and $ 2x+4 $ is $ 5x - 2 $. Solve for $ x $.
- Set equal to $ 5x - 2 $:
- \frac{7x + 12}{3} = 5x - 2 \implies 7x + 12 = 15x - 6 \implies -8x = -18 \implies x = \frac{9}{4}.
- The solution is $ \boxed{\frac{9}{4}} $.
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