We are selecting 5 buses from a total of $ 6 + 4 + 5 = 15 $ buses.
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- \frac{630}{1365} = \frac{6}{13}
- \boxed{\frac{6}{13}}
- Question: A transportation analyst is analyzing a network with 6 red buses, 4 green buses, and 5 blue buses. If she randomly selects 5 buses for maintenance, what is the probability that she selects at least two buses of each color?
- We want the probability that the selection includes **at least two buses of each color**.
- ### Step 1: Total number of ways to choose 5 buses from 15:
- \text{Total ways} = \binom{15}{5} = 3003
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